-5x^2-28x-23=0

Solution for -5x^2-28x-23=0 equation:

-5x^2-28x-23=0

a = -5; b = -28; c = -23;
Δ = b2-4ac
Δ = -282-4·(-5)·(-23)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-18}{2*-5}=\frac{10}{-10}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+18}{2*-5}=\frac{46}{-10}
=-4+3/5
$